Question on: JAMB Mathematics - 2008
What is the mean of the data t, 2t - 1, t - 2, 2t - 1, 4t and 2t + 2?
A
2t
B
2t - 1
C
\(\frac{2}{3}\)t + 1
D
2t - \(\frac{1}{3}\)
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Correct Option: D
\(\frac{t + 2t - 1 + t - 2 + 2t - 1 + 4t + 2t + 2}{6}\)
= \(\frac{12t - 2}{6}\)
= \(\frac {12t}{6}\) - \(\frac{2}{6}\)
= 2t - \(\frac{1}{3}\)
= \(\frac{12t - 2}{6}\)
= \(\frac {12t}{6}\) - \(\frac{2}{6}\)
= 2t - \(\frac{1}{3}\)
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